The expression
$\displaystyle {\frac{{{\left({16}{s}^{{-{3}}}{t}^{{{5}}}\right)}^{{{3}/{2}}}}}{{{\left({64}{s}^{{{2}}}{t}^{{-{3}}}\right)}^{{{2}/{3}}}}}}$

equals $\displaystyle {n}\frac{{t}^{{a}}}{{s}^{{b}}}$ where
n, the coefficient, is: Preview Question 6 Part 1 of 3  
a, the exponent of t, is: Preview Question 6 Part 2 of 3  
b, the exponent of s, is: Preview Question 6 Part 3 of 3