The expression (5t2)(4t+4)+2t4\displaystyle {\left({5}{t}-{2}\right)}{\left({4}{t}+{4}\right)}+{2}{t}-{4} equals At2+Bt+C\displaystyle {A}{t}^{{2}}+{B}{t}+{C}
where A\displaystyle {A} equals:


and B\displaystyle {B} equals:


and C\displaystyle {C} equals: