Given the function
P ( x ) = x 3 − 1 x 2 − 2 x \displaystyle {P}{\left({x}\right)}={x}^{{3}}-{1}{x}^{{2}}-{2}{x} P ( x ) = x 3 − 1 x 2 − 2 x , find
its
y \displaystyle {y} y -intercept is
Preview Question 6 Part 1 of 6
its
x \displaystyle {x} x -intercepts are
x 1 = \displaystyle {x}_{{1}}= x 1 = Preview Question 6 Part 2 of 6 ,
x 2 = \displaystyle {x}_{{2}}= x 2 = Preview Question 6 Part 3 of 6 and
x 3 = \displaystyle {x}_{{3}}= x 3 = Preview Question 6 Part 4 of 6 with
x 1 < x 2 < x 3 \displaystyle {x}_{{1}}<{x}_{{2}}<{x}_{{3}} x 1 < x 2 < x 3
When
x → ∞ \displaystyle {x}\to\infty x → ∞ ,
y → \displaystyle {y}\to y → ∞ \displaystyle \infty ∞
(Input + or - for the answer)
When
x → − ∞ \displaystyle {x}\to-\infty x → − ∞ ,
y → \displaystyle {y}\to y → ∞ \displaystyle \infty ∞
(Input + or - for the answer)
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