Given the function P(x)=(x2)(x+6)\displaystyle {P}{\left({x}\right)}={\left({x}-{2}\right)}{\left({x}+{6}\right)}, find
its y\displaystyle {y}-intercept is  
its x\displaystyle {x}-intercepts are x1=\displaystyle {x}_{{1}}=   and x2=\displaystyle {x}_{{2}}=   with x1x2\displaystyle {x}_{{1}}\le{x}_{{2}}
When x\displaystyle {x}\to\infty, y\displaystyle {y}\to \displaystyle \infty (Input + or - for the answer)
When x\displaystyle {x}\to-\infty, y\displaystyle {y}\to \displaystyle \infty (Input + or - for the answer)