Multiply and simplify:
x
2
+
4
x
+
3
x
+
4
⋅
x
−
5
x
+
3
\displaystyle \frac{{{x}^{{2}}+{4}{x}+{3}}}{{{x}+{4}}}\cdot\frac{{{x}-{5}}}{{{x}+{3}}}
x
+
4
x
2
+
4
x
+
3
⋅
x
+
3
x
−
5
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Question 6
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