Let
f
(
x
)
=
4
−
x
2
,
x
≥
0
\displaystyle {f{{\left({x}\right)}}}={4}-{x}^{{2}},\quad{x}\ge{0}
f
(
x
)
=
4
−
x
2
,
x
≥
0
f
−
1
(
x
)
=
\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=
f
−
1
(
x
)
=
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