Find all solutions of the system
{y=36x2y=x236\displaystyle {\left\lbrace\begin{array}{c} {y}={36}-{x}^{{2}}\\{y}={x}^{{2}}-{36}\end{array}\right.}
The two solutions of the system are:
the one with x<0\displaystyle {x}<{0} is
x=\displaystyle {x}=  
y=\displaystyle {y}=  

the one with x>0\displaystyle {x}>{0} is
x=\displaystyle {x}=  
y=\displaystyle {y}=