Solve the equation for the given variable. If your answer is a fraction, write it in reduced, fractional form. Do NOT convert the answer to a decimal.

5(4y5)+6=4(3y1)+1\displaystyle {5}{\left({4}{y}-{5}\right)}+{6}={4}{\left({3}{y}-{1}\right)}+{1}

Answer: y\displaystyle {y} =