Simplify the following completely:
A)
40
x
2
⋅
8
x
9
\displaystyle \sqrt{{{40}{x}^{{2}}}}\cdot\sqrt{{{8}{x}^{{9}}}}
40
x
2
⋅
8
x
9
Answer:
40
x
2
⋅
8
x
9
=
A
B
\displaystyle \sqrt{{{40}{x}^{{2}}}}\cdot\sqrt{{{8}{x}^{{9}}}}={A}\sqrt{{{B}}}
40
x
2
⋅
8
x
9
=
A
B
, where
A
=
\displaystyle {A}=
A
=
and
B
=
\displaystyle {B}=
B
=
Preview
A
\displaystyle {A}
A
:
Preview
Question 6 Part 1 of 4
Preview
B
\displaystyle {B}
B
:
Preview
Question 6 Part 2 of 4
B)
30
x
2
⋅
10
x
6
\displaystyle \sqrt{{{30}{x}^{{2}}}}\cdot\sqrt{{{10}{x}^{{6}}}}
30
x
2
⋅
10
x
6
Answer:
30
x
2
⋅
10
x
6
=
A
B
\displaystyle \sqrt{{{30}{x}^{{2}}}}\cdot\sqrt{{{10}{x}^{{6}}}}={A}\sqrt{{{B}}}
30
x
2
⋅
10
x
6
=
A
B
, where
A
=
\displaystyle {A}=
A
=
and
B
=
\displaystyle {B}=
B
=
Preview
A
\displaystyle {A}
A
:
Preview
Question 6 Part 3 of 4
Preview
B
\displaystyle {B}
B
:
Preview
Question 6 Part 4 of 4
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\displaystyle