The following inequality has a solution in the form x≤A.\displaystyle {x}\le{A}. Solve the inequality and place the correct value of A\displaystyle {A} into the box.

6(x+10)−1≤3x−10\displaystyle {6}{\left({x}+{10}\right)}-{1}\le{3}{x}-{10}

Answer: x≤\displaystyle {x}\le
Enter your answer as an integer or a reduced fraction in the form A/B.
 

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