The equation $\displaystyle {15}{r}^{{2}}+{4}{r}-{3}={0}$ has solutions of the form

$\displaystyle {r}=\frac{{{N}\pm\sqrt{{{D}}}}}{{M}}$

(A) Use the quadratic formula to solve this equation and find the appropriate integer values of $\displaystyle {N}$,$\displaystyle {M}$,and $\displaystyle {D}$. Do not worry about simplifying the $\displaystyle \sqrt{{{D}}}$ yet in this part of the problem. $\displaystyle {N}=$ ; $\displaystyle {D}=$
$\displaystyle {M}=$

(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2,-3/4 $\displaystyle {r}=$ Preview Question 6 Part 4 of 4