The height $\displaystyle {y}$ (in feet) of a ball thrown by a child is
$\displaystyle {y}=-{\frac{{{1}}}{{{12}}}}{x}^{{2}}+{4}{x}+{5}$
where $\displaystyle {x}$ is the horizontal distance in feet from the point at which the ball is thrown.
(a) How high is the ball when it leaves the child's hand? (Hint: Find $\displaystyle {y}$ when $\displaystyle {x}={0}$)
Your answer is $\displaystyle {y}=$ Preview Question 6 Part 1 of 3  
(b) What is the maximum height of the ball? Preview Question 6 Part 2 of 3  
(c) How far from the child does the ball strike the ground? Preview Question 6 Part 3 of 3