The expression 2(5x3+3x25x+7)(4x2+7x5)\displaystyle {2}{\left({5}{x}^{{3}}+{3}{x}^{{2}}-{5}{x}+{7}\right)}-{\left({4}{x}^{{2}}+{7}{x}-{5}\right)} equals
x3+\displaystyle {x}^{{3}}+ x2+\displaystyle {x}^{{2}}+ x+\displaystyle {x}+

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