Consider the parabola given by the equation:
$\displaystyle {y}={x}^{{2}}+{10}{x}-{12}$

Find the following for this parabola:

A) When $\displaystyle {x}=-{5}$ the value of $\displaystyle {y}$ is:

B) The vertex = (,)

C) The $\displaystyle {y}$ intercept is the point (0,)

D) Find the two values of $\displaystyle {x}$ that make $\displaystyle {y}={0}$. Round your answers to two decimal places. Write the values as a list, separated by commas:
$\displaystyle {x}=$