The expression (4x2+8x+1)(2x2+7x+4)\displaystyle {\left({4}{x}^{{2}}+{8}{x}+{1}\right)}{\left({2}{x}^{{2}}+{7}{x}+{4}\right)} equals x4+\displaystyle {x}^{{4}}+ x3+\displaystyle {x}^{{3}}+ x2+\displaystyle {x}^{{2}}+ x+\displaystyle {x}+