Using the Law of Sines to solve the all possible triangles if
∠ A = 108 ∘ , a = 33 , b = 19. \displaystyle \angle{A}={108}^{\circ},{a}={33},{b}={19}. ∠ A = 108 ∘ , a = 33 , b = 19 . If no answer exists, enter DNE for all answers.
∠ B \displaystyle \angle{B} ∠ B is
Preview Question 6 Part 1 of 3 degrees;
∠ C \displaystyle \angle{C} ∠ C is
Preview Question 6 Part 2 of 3 degrees;
c = \displaystyle {c}= c = Preview Question 6 Part 3 of 3 ;
Assume
∠ A \displaystyle \angle{A} ∠ A is opposite side
a \displaystyle {a} a ,
∠ B \displaystyle \angle{B} ∠ B is opposite side
b \displaystyle {b} b , and
∠ C \displaystyle \angle{C} ∠ C is opposite side
c \displaystyle {c} c .
Submit Try a similar question
[more..]
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)