If cos2xsin4x=A+Bcos2x+Ccos4x+Dcos2xcos4x\displaystyle {{\cos}^{{2}}{x}}{{\sin}^{{4}}{x}}={A}+{B}{\cos{{2}}}{x}+{C}{\cos{{4}}}{x}+{D}{\cos{{2}}}{x}{\cos{{4}}}{x}, then
A=\displaystyle {A}=   ,
B=\displaystyle {B}=   ,
C=\displaystyle {C}=   ,
D=\displaystyle {D}=   .