Find
tan
(
u
2
)
\displaystyle {\tan{{\left(\frac{{u}}{{2}}\right)}}}
tan
(
2
u
)
if
sin
u
=
−
0.423
\displaystyle {\sin{{u}}}=-{0.423}
sin
u
=
−
0.423
and
u
\displaystyle {u}
u
is in Quadrant-III.
tan
(
u
2
)
=
\displaystyle {\tan{{\left(\frac{{u}}{{2}}\right)}}}=
tan
(
2
u
)
=
Your answer should be accurate to 4 decimal places.
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