For
sin 3 x + sin x = 0 , \displaystyle {\sin{{3}}}{x}+{\sin{{x}}}={0}, sin 3 x + sin x = 0 ,
use a sum-to-product formula to simplify the equation and then
find all solutions of the equation
in the interval
[ 0 , π ) . \displaystyle {\left[{0},\pi\right)}. [ 0 , π ) .
The answer is
x 1 = \displaystyle {x}_{{1}}= x 1 = Preview Question 6 Part 1 of 2 and
x 2 = \displaystyle {x}_{{2}}= x 2 = Preview Question 6 Part 2 of 2
with
x 1 < x 2 \displaystyle {x}_{{1}}\lt{x}_{{2}} x 1 < x 2 .
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)