Solve for t\displaystyle {t}, 0t<2π\displaystyle {0}\le{t}<{2}\pi

18sin2(t)=8tan(t)cos(t)\displaystyle {18}{{\sin}^{{2}}{\left({t}\right)}}={8}{\tan{{\left({t}\right)}}}{\cos{{\left({t}\right)}}}

t\displaystyle {t} =  

Give your answers accurate to at least two decimal places, as a list separated by commas