Let
a
⃗
=
−
2
i
⃗
+
2
j
⃗
\displaystyle \vec{{a}}=-{2}\vec{{{i}}}+{2}\vec{{{j}}}
a
=
−
2
i
+
2
j
and
b
⃗
=
−
4
i
⃗
−
3
j
⃗
\displaystyle \vec{{b}}=-{4}\vec{{{i}}}-{3}\vec{{{j}}}
b
=
−
4
i
−
3
j
. Find
a
⃗
⋅
b
⃗
\displaystyle \vec{{a}}\cdot\vec{{b}}
a
⋅
b
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