Given the vector u⃗=⟨−6,−4⟩\displaystyle \vec{{u}}={\left\langle-{6},-{4}\right\rangle}, find the magnitude and angle in which the vector points (measured counterclockwise from the positive x-axis, 0≤θ<2π\displaystyle {0}\le\theta\lt{2}\pi)

∣∣u⃗∣∣\displaystyle {\left|{\left|\vec{{u}}\right|}\right|} =  

θ\displaystyle \theta =  

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