Let $\displaystyle {f{{\left({x}\right)}}}={\frac{{{6}{x}+{12}}}{{{x}^{{2}}-{4}{x}-{12}}}}$.

Calculate $\displaystyle \lim_{{{x}\to-{2}}}{f{{\left({x}\right)}}}$ by first finding a continuous function which is equal to $\displaystyle {f}$ everywhere except $\displaystyle {x}=-{2}$.

$\displaystyle \lim_{{{x}\to-{2}}}{f{{\left({x}\right)}}}=$ Preview Question 6