For each slope below, enter the value correct to four decimal places.

Let f(x)=2ln(x)\displaystyle {f{{\left({x}\right)}}}={2}{\ln{{\left({x}\right)}}}. Using the formula, m=f(x2)f(x1)x2x1\displaystyle {m}=\frac{{{f{{\left({x}_{{{2}}}\right)}}}-{f{{\left({x}_{{{1}}}\right)}}}}}{{{x}_{{{2}}}-{x}_{{{1}}}}}, find the slope of the secant line on the graph of f(x)\displaystyle {f{{\left({x}\right)}}} that connects the points x1=9\displaystyle {x}_{{{1}}}={9} and ...

...x2=14\displaystyle {x}_{{{2}}}={14}:   m=\displaystyle {m}=  

...x2=11\displaystyle {x}_{{{2}}}={11}:   m=\displaystyle {m}=  

...x2=10\displaystyle {x}_{{{2}}}={10}:   m=\displaystyle {m}=  

...x2=9.1\displaystyle {x}_{{{2}}}={9.1}:   m=\displaystyle {m}=  

...x2=9.01\displaystyle {x}_{{{2}}}={9.01}:   m=\displaystyle {m}=