Let $\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{ccc} -{2}{x}+{b}&\text{if}&{x}<-{4}\\{\frac{{-{96}}}{{{x}-{b}}}}&\text{if}&{x}\geq-{4}\end{array}\right.}$
There are exactly two values for $\displaystyle {b}$ which make $\displaystyle {f{{\left({x}\right)}}}$ a continuous function at $\displaystyle {x}=-{4}$. The one with the greater absolute value is
$\displaystyle {b}=$Preview Question 6  
Now for fun, try to graph $\displaystyle {f{{\left({x}\right)}}}$.