Find
c
\displaystyle {c}
c
such that the function
f
(
x
)
=
{
x
2
−
7
x
≤
c
8
x
−
23
x
>
c
.
\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{cc} {x}^{{2}}-{7}&{x}\le{c}\\{8}{x}-{23}&{x}>{c}\end{array}\right.}.
f
(
x
)
=
{
x
2
−
7
8
x
−
23
x
≤
c
x
>
c
.
is continuous everywhere.
c
=
\displaystyle {c}=
c
=
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