Objective [1.8]
If f(x)=xe0.1x\displaystyle {f{{\left({x}\right)}}}={x}\cdot{e}^{{-{0.1}{x}}}, find dfdxx=4\displaystyle \frac{{{d}{f}}}{{\left.{d}{x}\right.}}{\mid}_{{{x}={4}}}.

nearest 0.001