If
h ( x ) = 4 − 3 x 3 \displaystyle {h}{\left({x}\right)}={4}-{3}{x}^{{3}} h ( x ) = 4 − 3 x 3 , find
h ′ ( 2 ) \displaystyle {h}'{\left({2}\right)} h ′ ( 2 ) .
Preview Question 6 Part 1 of 3
Use this to find the equation of the tangent line to the curve
y = 4 − 3 x 3 \displaystyle {y}={4}-{3}{x}^{{3}} y = 4 − 3 x 3
at the point
( 2 , − 20 ) \displaystyle {\left({2},-{20}\right)} ( 2 , − 20 ) .
The equation of this tangent line can be written in the form
y = m x + b \displaystyle {y}={m}{x}+{b} y = m x + b
where
m \displaystyle {m} m is:
Preview Question 6 Part 2 of 3
and where
b \displaystyle {b} b is:
Preview Question 6 Part 3 of 3 Submit Try a similar question
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)