On a separate piece of paper, sketch the graph of the parabola y=x2+7\displaystyle {y}={x}^{{2}}+{7}. On the same graph, plot the point (0,5)\displaystyle {\left({0},-{5}\right)}. Note that there are two tangent lines of y=x2+7\displaystyle {y}={x}^{{2}}+{7} that pass through the point (0,5)\displaystyle {\left({0},-{5}\right)}.

Specifically, the tangent line of the parabola y=x2+7\displaystyle {y}={x}^{{2}}+{7} at the point (a,a2+7)\displaystyle {\left({a},{a}^{{2}}+{7}\right)} passes through the point (0,5)\displaystyle {\left({0},-{5}\right)} where a>0\displaystyle {a}>{0}. The other tangent line that passes through the point (0,5)\displaystyle {\left({0},-{5}\right)} occurs at the point (a,a2+7)\displaystyle {\left(-{a},{a}^{{2}}+{7}\right)}.

Find the number a\displaystyle {a}.