Let $\displaystyle {f{{\left({x}\right)}}}={x}^{{3}}-{6}{x}+{15}$. Then the equation of the tangent line to the graph of $\displaystyle {f{{\left({x}\right)}}}$ at the point $\displaystyle {\left(-{1},{20}\right)}$ is given by $\displaystyle {y}={m}{x}+{b}$ for

$\displaystyle {m}=$Preview Question 6 Part 1 of 2  


and
$\displaystyle {b}=$ Preview Question 6 Part 2 of 2   .