A particle moves along a straight line with equation of motion
s
=
t
6
−
3
t
5
\displaystyle {s}={t}^{{{6}}}-{3}{t}^{{{5}}}
s
=
t
6
−
3
t
5
. Find the value of
t
\displaystyle {t}
t
(other than 0 ) at which the acceleration is equal to zero.
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity