A particle moves along a straight line and its position at time t\displaystyle {t} is given by s(t)=2t330t2+126t\displaystyle {s}{\left({t}\right)}={2}{t}^{{3}}-{30}{t}^{{2}}+{126}{t} where s is measured in feet and t in seconds.

Find the velocity (in ft/sec) of the particle at time t=0\displaystyle {t}={0}:  

The particle stops moving (i.e. is in a rest) twice,
first when t\displaystyle {t} =   ,
and again when t\displaystyle {t} =  

What is the position of the particle at time 20\displaystyle {20}?   ft

Finally, what is the TOTAL distance the particle travels between time 0\displaystyle {0} and time 20\displaystyle {20}?   ft