A particle moves along a straight line and its position at time
t
is given by
s(t)=2t3−24t2+42t where s is measured in feet and
t in seconds.
Find the velocity (in ft/sec) of the particle at time
t=0:
The particle stops moving (i.e. is in a rest) twice,
first when
t =
,
and again when
t =
What is the position of the particle at time
16?
ft
Finally, what is the TOTAL distance the particle travels between time
0 and
time
16?
ft
[more..]
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity