Find the derivative of
f
(
x
)
=
3
x
3
+
5
x
2
+
2
x
+
5
\displaystyle {f{{\left({x}\right)}}}={3}{x}^{{3}}+{5}{x}^{{2}}+{2}{x}+{5}
f
(
x
)
=
3
x
3
+
5
x
2
+
2
x
+
5
and place your answer below.
Answer:
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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