If f(x)=2x48ex\displaystyle {f{{\left({x}\right)}}}={2}{x}^{{{4}}}-{8}{e}^{{x}}, find:

f(x)\displaystyle {f}'{\left({x}\right)} =  
f(4)\displaystyle {f}'{\left({4}\right)} =  

f(x)\displaystyle {f}{''}{\left({x}\right)} =  
f(4)\displaystyle {f}{''}{\left({4}\right)} =