If f(x)=2x2tanxsecx\displaystyle {f{{\left({x}\right)}}}={\frac{{{2}{x}^{{2}}{\tan{{x}}}}}{{{\sec{{x}}}}}}, find
f(x)\displaystyle {f}'{\left({x}\right)} =  

Find f(2)\displaystyle {f}'{\left({2}\right)}=