If f(x)=9x3ln⁡(4x)\displaystyle {f{{\left({x}\right)}}}={9}{x}^{{{3}}}{\ln{{\left({4}{x}\right)}}}, then
f′(x)=\displaystyle {f}'{\left({x}\right)}=  
f′′(x)=\displaystyle {f}{''}{\left({x}\right)}=  
f′′′(x)=\displaystyle {f}{'''}{\left({x}\right)}=  
f(4)(x)=\displaystyle {{f}^{{{\left({4}\right)}}}{\left({x}\right)}}=  
f(5)(x)=\displaystyle {{f}^{{{\left({5}\right)}}}{\left({x}\right)}}=  

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