If f(x)=5x2+8x+5x,\displaystyle {f{{\left({x}\right)}}}={\frac{{{5}{x}^{{2}}+{8}{x}+{5}}}{{\sqrt{{{x}}}}}},, then:

f(x)\displaystyle {f}'{\left({x}\right)} =  

f(5)\displaystyle {f}'{\left({5}\right)} =