If f(x)=5x2+5x+4x,\displaystyle {f{{\left({x}\right)}}}={\frac{{{5}{x}^{{2}}+{5}{x}+{4}}}{{\sqrt{{{x}}}}}},, then:

f(x)\displaystyle {f}'{\left({x}\right)} =  

f(2)\displaystyle {f}'{\left({2}\right)} =