Let
f
(
x
)
=
(
x
+
2
x
+
4
)
8
\displaystyle {f{{\left({x}\right)}}}={\left(\frac{{{x}+{2}}}{{{x}+{4}}}\right)}^{{8}}
f
(
x
)
=
(
x
+
4
x
+
2
)
8
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
Preview
Question 6
Question Help:
Video
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question