If
f
(
x
)
=
3
x
+
9
\displaystyle {f{{\left({x}\right)}}}=\sqrt{{{3}{x}+{9}}}
f
(
x
)
=
3
x
+
9
, find
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
.
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