Let $\displaystyle {F}{\left({x}\right)}={f{{\left({x}^{{{9}}}\right)}}}$ and $\displaystyle {G}{\left({x}\right)}={\left({f{{\left({x}\right)}}}\right)}^{{{9}}}$ .
You also know that $\displaystyle {a}^{{{8}}}={13},{f{{\left({a}\right)}}}={3},{f}'{\left({a}\right)}={9},{f}'{\left({a}^{{{9}}}\right)}={6}$

Then $\displaystyle {F}'{\left({a}\right)}=$ Preview Question 6 Part 1 of 2   and $\displaystyle {G}'{\left({a}\right)}=$ Preview Question 6 Part 2 of 2