Let
f
(
x
)
=
4
cos
(
cos
x
)
\displaystyle {f{{\left({x}\right)}}}={4}{\cos{{\left({\cos{{x}}}\right)}}}
f
(
x
)
=
4
cos
(
cos
x
)
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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