Let
f
(
x
)
=
−
4
cos
3
x
\displaystyle {f{{\left({x}\right)}}}=-{4}{{\cos}^{{{3}}}{x}}
f
(
x
)
=
−
4
cos
3
x
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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