Let
f
(
x
)
=
(
−
9
x
2
+
8
)
3
(
−
5
x
2
+
5
)
14
\displaystyle {f{{\left({x}\right)}}}={\left(-{9}{x}^{{2}}+{8}\right)}^{{{3}}}{\left(-{5}{x}^{{2}}+{5}\right)}^{{{14}}}
f
(
x
)
=
(
−
9
x
2
+
8
)
3
(
−
5
x
2
+
5
)
14
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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