If
f
(
x
)
=
3
sin
(
7
x
)
sin
−
1
(
x
)
\displaystyle {f{{\left({x}\right)}}}={3}{\sin{{\left({7}{x}\right)}}}{{\sin}^{{-{{1}}}}{\left({x}\right)}}
f
(
x
)
=
3
sin
(
7
x
)
sin
−
1
(
x
)
,
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
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