Let
f
(
x
)
=
tan
−
1
(
sin
(
5
x
)
)
\displaystyle {f{{\left({x}\right)}}}={{\tan}^{{-{1}}}{\left({\sin{{\left({5}{x}\right)}}}\right)}}
f
(
x
)
=
tan
−
1
(
sin
(
5
x
)
)
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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