Let
f
(
x
)
=
ln
(
8
x
−
4
5
x
+
6
)
\displaystyle {f{{\left({x}\right)}}}={\ln{{\left(\sqrt{{{\frac{{{8}{x}-{4}}}{{{5}{x}+{6}}}}}}\right)}}}
f
(
x
)
=
ln
(
5
x
+
6
8
x
−
4
)
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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