If f(x)=8ln(8x+3ln(x))\displaystyle {f{{\left({x}\right)}}}={8}{\ln{{\left({8}{x}+{3}{\ln{{\left({x}\right)}}}\right)}}},

f(x)\displaystyle {f}'{\left({x}\right)} =  

f(2)\displaystyle {f}'{\left({2}\right)} =