Let f(x)=x2+3\displaystyle {f{{\left({x}\right)}}}=\sqrt{{{x}^{{2}}+{3}}}.
Then f(x)\displaystyle {f}'{\left({x}\right)} is  
f(3)\displaystyle {f}'{\left({3}\right)} is   ,


f(x)\displaystyle {f}{''}{\left({x}\right)} is  
and f(3)\displaystyle {f}{''}{\left({3}\right)} is