Let g(s)=(3s4)8\displaystyle {g{{\left({s}\right)}}}={\left({3}{s}-{4}\right)}^{{8}}.
Then g(s)\displaystyle {g}'{\left({s}\right)} is  
g(4)\displaystyle {g}'{\left({4}\right)} is   ,

g(s)\displaystyle {g}{''}{\left({s}\right)} is  
and g(4)\displaystyle {g}{''}{\left({4}\right)} is