Use implicit differentiation to find the slope of the tangent line to the curve
yx+2y=x8+2\displaystyle {\frac{{{y}}}{{{x}+{2}{y}}}}={x}^{{{8}}}+{2}
at the point (1,35)\displaystyle {\left({1},{\frac{{{3}}}{{-{5}}}}\right)}.

slope =